qsbb @ 2024-08-27 19:48:00
#include<bits/stdc++.h>
using namespace std;
int n;
int a[1000010];
int main(){
cin >> n;
for(int i = 0; i < n; i++) cin >> a[i];
int num = 0;
for(int i = 0; i < n; i++){
for(int j = 0; j < n; j--){
int k = sqrt(a[i] + a[j]);
if(a[i] + a[j] == k * k){
num ++;
}
}
}
cout << num;
}
by kanqiqin @ 2024-08-27 19:53:15
#include <bits/stdc++.h>
using namespace std;
int a[1010];
bool pf(int x)
{
if((int)sqrt(x) * (int)sqrt(x) == x)
{
return true;
}
return false;
}
int main()
{
int n;
cin >> n;
for(int i = 1; i <= n; i++)
{
cin >> a[i];
}
int cnt = 0;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j < i; j++)
{
if(pf(a[i] + a[j]))
{
cnt++;
}
}
}
cout << cnt << endl;
return 0;
}
by meifan666 @ 2024-08-27 19:53:22
@just01
by kanqiqin @ 2024-08-27 19:53:47
球关
by meifan666 @ 2024-08-27 19:53:57
@just01 还有,要判断到n
by Dress @ 2024-08-27 19:56:32
@just01 已AC求关QWQ
#include<bits/stdc++.h>
using namespace std;
int n;
int a[1000010];
int main(){
cin >> n;
for(int i = 0; i < n; i++) cin >> a[i];
int num = 0;
for(int i = 0; i < n; i++){
for(int j = i + 1; j < n; j++){//j = 0 -> j = i + 1 j-- -> j++
int k = sqrt((int) a[i] + a[j]);//sqrt(a[i] + a[j]) -> sqrt((int) a[i] + a[j])
if(sqrt(a[i] + a[j]) == k){//a[i] + a[j] == k * k -> sqrt(a[i] + a[j]) == k
num ++;
}
}
}
cout << num;
}
AC记录