lvcb248 @ 2024-08-27 20:16:16
#include<stdio.h>
int main()
{
int n=0,i=0,u=0;
int a[100];
scanf("%d",&n);
for(i=0;i<=n-1;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n-1;i++)
{
switch(a[i])
{
case 0:
printf("XXX.");
break;
case 1:
printf("..X.");
break;
case 2:
printf("XXX.");
break;
case 3:
printf("XXX.");
break;
case 4:
printf("X.X.");
break;
case 5:
printf("XXX.");
break;
case 6:
printf("XXX.");
break;
case 7:
printf("XXX.");
break;
case 8:
printf("XXX.");
break;
case 9:
printf("XXX.");
break;
}
}
switch(a[n-1])
{
case 0:
printf("XXX\n");
break;
case 1:
printf("..X\n");
break;
case 2:
printf("XXX\n");
break;
case 3:
printf("XXX\n");
break;
case 4:
printf("X.X\n");
break;
case 5:
printf("XXX\n");
break;
case 6:
printf("XXX\n");
break;
case 7:
printf("XXX\n");
break;
case 8:
printf("XXX\n");
break;
case 9:
printf("XXX\n");
break;
}
for(i=0;i<n-1;i++)
{
switch(a[i])
{
case 0:
printf("X.X.");
break;
case 1:
printf("..X.");
break;
case 2:
printf("..X.");
break;
case 3:
printf("..X.");
break;
case 4:
printf("X.X.");
break;
case 5:
printf("X...");
break;
case 6:
printf("X...");
break;
case 7:
printf("..X.");
break;
case 8:
printf("X.X.");
break;
case 9:
printf("X.X.");
break;
}
}
switch(a[n-1])
{
case 0:
printf("X.X\n");
break;
case 1:
printf("..X\n");
break;
case 2:
printf("..X\n");
break;
case 3:
printf("..X\n");
break;
case 4:
printf("X.X\n");
break;
case 5:
printf("X..\n");
break;
case 6:
printf("X..\n");
break;
case 7:
printf("..X\n");
break;
case 8:
printf("X.X\n");
break;
case 9:
printf("X.X\n");
break;
}
for(i=0;i<n-1;i++)
{
switch(a[i])
{
case 0:
printf("X.X.");
break;
case 1:
printf("..X.");
break;
case 2:
printf("XXX.");
break;
case 3:
printf("XXX.");
break;
case 4:
printf("XXX.");
break;
case 5:
printf("XXX.");
break;
case 6:
printf("XXX.");
break;
case 7:
printf("..X.");
break;
case 8:
printf("XXX.");
break;
case 9:
printf("XXX.");
break;
}
}
switch(a[n-1])
{
case 0:
printf("X.X\n");
break;
case 1:
printf("..X\n");
break;
case 2:
printf("XXX\n");
break;
case 3:
printf("XXX\n");
break;
case 4:
printf("XXX\n");
break;
case 5:
printf("XXX\n");
break;
case 6:
printf("XXX\n");
break;
case 7:
printf("..X\n");
break;
case 8:
printf("XXX\n");
break;
case 9:
printf("XXX\n");
break;
}
for(i=0;i<n-1;i++)
{
switch(a[i])
{
case 0:
printf("X.X.");
break;
case 1:
printf("..X.");
break;
case 2:
printf("X...");
break;
case 3:
printf("..X.");
break;
case 4:
printf("..X.");
break;
case 5:
printf("..X.");
break;
case 6:
printf("X.X.");
break;
case 7:
printf("..X.");
break;
case 8:
printf("X.X.");
break;
case 9:
printf("..X.");
break;
}
}
switch(a[n-1])
{
case 0:
printf("X.X\n");
break;
case 1:
printf("..X\n");
break;
case 2:
printf("X..\n");
break;
case 3:
printf("..X\n");
break;
case 4:
printf("..X\n");
break;
case 5:
printf("..X\n");
break;
case 6:
printf("X.X\n");
break;
case 7:
printf("..X\n");
break;
case 8:
printf("X.X\n");
break;
case 9:
printf("..X\n");
break;
}
for(i=0;i<n-1;i++)
{
switch(a[i])
{
case 0:
printf("XXX.");
break;
case 1:
printf("..X.");
break;
case 2:
printf("XXX.");
break;
case 3:
printf("XXX.");
break;
case 4:
printf("..X.");
break;
case 5:
printf("XXX.");
break;
case 6:
printf("XXX.");
break;
case 7:
printf("..X.");
break;
case 8:
printf("XXX.");
break;
case 9:
printf("XXX");
break;
}
}
switch(a[n-1])
{
case 0:
printf("XXX.");
break;
case 1:
printf("..X");
break;
case 2:
printf("XXX");
break;
case 3:
printf("XXX");
break;
case 4:
printf("..X");
break;
case 5:
printf("XXX");
break;
case 6:
printf("XXX");
break;
case 7:
printf("..X");
break;
case 8:
printf("XXX");
break;
case 9:
printf("XXX");
break;
}
return 0;
} by Curry_mvp @ 2024-08-27 20:17:18
！
by dongzirui0817 @ 2024-08-27 20:28:01
@lvcb248 请注意输入方式。
by Yxy7952 @ 2024-08-27 20:31:02
@lvcb248
???????，不是，楼主，输入都有问题，建议做字符串入门题
by Yxy7952 @ 2024-08-27 20:32:15
@dongzirui0817
楼主是真逆天，写了这么多，样例都有问题，就敢交
by dongzirui0817 @ 2024-08-27 20:32:58
@lvcb248 你程序还有些问题……
by dongzirui0817 @ 2024-08-27 20:37:37
@lvcb248 第337行\
printf("XXX");\
改成\
printf("XXX.");
by lvcb248 @ 2024-08-27 22:18:03
@yixingyou 我在dev c++样例过了哩，可以说说我的输入哪里有问题吗，至于字符串我还没学
by Yxy7952 @ 2024-08-28 09:46:32
@lvcb248 \
给楼主讲一下，这是样例：
10
0123456789这是你的输入：
int a[100];
scanf("%d",&n);
for(i=0;i<=n-1;i++){
scanf("%d",&a[i]);
}
这是题目原话:
第二行输入一个长度为 n 的自然数显然样例的第二行是 一个数字 或者可以理解为 一串字符串 ，但你的输入方式却理解成了有
楼主应该先把输入的第二行当作字符串处理，并手动改为
by lvcb248 @ 2024-08-28 14:34:31
@yixingyou 噢噢，懂了