abababwosb @ 2024-09-04 09:03:27
#include <bits/stdc++.h>
using namespace std;
double dis(double a1, double b1, double a2, double b2) {
int tmp;
tmp = sqrt(pow((a1 - a2), 2) + pow((b1 - b2), 2));
return tmp;
}
int main() {
double a1, a2, a3, b1, b2, b3, tmp = 0;
cin >> a1 >> b1 >> a2 >> b2 >> a3 >> b3;
tmp += dis(a1, b1, a2, b2);
tmp += dis(a1, b1, a3, b3);
tmp += dis(a2, b2, a3, b3);
printf("%.2f", tmp);
return 0;
}
by Hollow_Knight @ 2024-09-04 09:13:00
有没有一种可能,你dis函数返回值是int类型的变量
by Hollow_Knight @ 2024-09-04 09:13:10
@abababwosb
by abababwosb @ 2024-09-04 09:34:43
说得对 @Hollow_Knight