Bareks @ 2024-09-15 10:41:35
#include<bits/stdc++.h>
using namespace std;
int main()
{
char a[11];
int len,i;
scanf("%s",a);
len=strlen(a);
if(a[0]==0) return 0;
if(a[0]=='-')
{
printf("-");
for(i=len-1;i>=1;i--)
{
if(a[i]!='0')
break;
}
for(;i>=1;i--)
{
printf("%c",a[i]);
}
}
else
{
for(i=len-1;i>=0;i--)
{
if(a[i]!='0')break;
}
for(;i>=0;i--)
printf("%c",a[i]);
if(a[i]==0)
{
std::cout<<0;
}
}
return 0;
}
为何是50分?
by pmkmzfuzsotqotmzs @ 2024-09-15 10:51:45
@Bareks
#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
if(n==0)
cout<<0<<endl;
else
{
bool flag=false;
if(n<0)
{
cout<<'-';
n=-n;
}
do
{
int a=n%10;
if(a!=0)
flag=true;
n=n/10;
if(a>0||(a==0&&flag))
cout<<a;
}
while(n!=0);
}
return 0;
}
by _th_tw_on_ @ 2024-09-15 11:01:30
数据范围小,用不着这么麻烦
#include<bits/stdc++.h>
using namespace std;
int n,ans;
int main(){
cin>>n;
if(n<0)cout<<"-";
n=abs(n);
while(n){
ans=ans*10+n%10,n/=10;
}
cout<<ans;
return 0;
}