第一个应该是$(\log n)\times(\log n)$ 罢
by untitled_cpp @ 2024-09-20 21:06:04
logn的平方和logn再log一下当然不一样了
by dhgzh @ 2024-09-20 21:06:36
@[qW__Wp](/user/453555) $\log^2 n=\log n\times\log n<\log\log n$
by asas111 @ 2024-09-20 21:06:44
@[qW__Wp](/user/453555)
$( \log n)^2$
$\log \log n$
by tireden @ 2024-09-20 21:06:57
多谢，懂了
by qW__Wp @ 2024-09-20 21:07:37
@[asas111](/user/661096)
$log^2n=logn×logn>loglogn\$吧
by ririTLE @ 2024-09-20 21:11:02
@[ririTLE](/user/788881) 打反了..
by asas111 @ 2024-09-20 21:11:51