Fjy20130703 @ 2024-09-25 21:07:28

#include<bits/stdc++.h>

using namespace std;

int a;

int main(){

    cin>>a;

    while(a!=1){

        if(a%2==1){

            a*=3;

            a+=1;

            cout<<(a-1)/3<<"*3+1="<<a;

        }else{

            a/=2;

            cout<<a*2<<"/2="<<a;
        }
    }
    return 0;
}

by fxwqctb @ 2024-09-25 21:10:04

输出没换行
每加 End

by LosTcrab @ 2024-09-25 21:31:03

在每次输出后加上endl，换下行。特判一下a==1时输出End，t的话建议开下longlong和ios

by luoyebushiye @ 2024-09-25 21:33:03

@Fjy20130703

应该不是用int的吧awa

by tuonisitake @ 2024-09-25 23:52:36

我这样写你应该能看懂把。

#include <stdio.h>

int main()
{
    long long n;
    scanf("%lld",&n);
    while (n!=1)
    {
        if(n%2==0)
        {
            printf("%lld/2=",n);
            n/=2;
            printf("%lld\n",n);
        }

        else if(n%2!=0){
            printf("%lld*3+1=",n);
            n=n*3+1;
            printf("%lld\n",n);
        }
    }
    printf("End");
    return 0;
}

by Fjy20130703 @ 2024-09-26 19:14:40

Thank you

by Fjy20130703 @ 2024-09-26 19:18:37

以全部回关

by gaohuashengtx @ 2024-12-22 20:59:22

@Fjy20130703 这样写更简单

#include<bits/stdc++.h>
using namespace std;
int main() {
    long long n;
    cin>>n;
    while(n>1){
        if(n%2==0){
            cout<<n<<"/2="<<n/2<<endl;
            if(n/2==1)break;
            n/=2;
        }
        else{
            cout<<n<<"*3+1="<<n*3+1<<endl;
            n=n*3+1;
        }
    }
    cout<<"End"<<endl;
      return 0;
}

你可以试试