$t$ 满足 $10\leqslant t\leqslant 1440$。
$$\begin{aligned}&\left(8+\left\lfloor\dfrac{86400-t}{60}\right\rfloor\right)\bmod 24\\=&\left(1424+\left\lfloor\dfrac{1440-t}{60}\right\rfloor\right)\bmod 24\\=&\left(8+\left\lfloor\dfrac{1440-t}{60}\right\rfloor\right)\bmod 24\end{aligned}$$
详见[同余](https://oi-wiki.org/math/number-theory/basic/#%E5%90%8C%E4%BD%99)。
by Terrible @ 2024-10-04 16:57:13