风水戏诸侯 @ 2019-01-21 17:20:01

by Luban @ 2019-01-21 17:47:46

早上刚AC了此题，直接全部都是int型即可

AC代码：（抄袭？变棕吧！）

#include<bits/stdc++.h>
using namespace std;
int a[1000],*top;
char s[1000];
void push(int x)
{
    *top=*top+1;
    a[*top]=x;
}
void pop()
{
    a[*top]=0;
    *top=*top-1;
}
int main()
{
    top=&a[0];
    scanf("%s",s);
    int i=0,r=1,j,ans,y,z;
    while(i<strlen(s))
    {
        if (s[i]=='.')
        {
            ans=0;
            r=1;
            j=i-1;
            while(s[j]>='0'&&s[j]<='9'&&j>=0)
            {
                ans=ans+r*(s[j]-'0');
                r=r*10;
                j=j-1;
            }
            push(ans);
        }
        if (s[i]=='@')
        {
            cout<<a[1]<<endl;
            return 0;
        }
        if (s[i]=='+')
        {
            y=a[*top];
            z=a[*top-1];
            pop();
            pop();
            push(y+z);
        }
        if (s[i]=='-')
        {
            y=a[*top];
            z=a[*top-1];
            pop();
            pop();
            push(z-y);
        }
        if (s[i]=='*')
        {
            y=a[*top];
            z=a[*top-1];
            pop();
            pop();
            push(y*z);
        }
        if (s[i]=='/')
        {
            y=a[*top];
            z=a[*top-1];
            pop();
            pop();
            push(z/y);
        }
        i=i+1;
    }
}

by difficult @ 2019-05-19 11:19:50

数据都是整型吗？

by y_kx_b @ 2022-08-22 11:34:44

@Light_Of_Wisdom tlqtj 烤谷*3