Qf_fd @ 2024-10-09 15:09:18
#include <stdio.h>
int main()
{
int n;
scanf("%d", &n);
while (n > 1)
{
if (n % 2 == 0)
{
printf("%d/2=%d\n", n, n / 2);
n = n / 2;
}
else
{
printf("%d*3+1=%d\n", n, n * 3 + 1);
n = n * 3 + 1;
}
}
printf("End");
return 0;
}
by jianhe @ 2024-10-09 15:22:01
@Qf_fd 开 long long
by Qf_fd @ 2024-10-09 17:03:29
@jianhe 谢谢你!