NoWalnut @ 2024-10-18 00:05:06

#include<iostream>
#include<cstdio>
using namespace std;
int main(){
    int N;
    scanf("%d",&N);
    getchar();
    char s[50];
    char name[N][20];
    int a[N],b[N],c[N];
    int sum[N];
    int max=-1;
    int std;
    for(int i=0;i<N;i++){
        fgets(s,sizeof(s),stdin);
        sscanf(s,"%s %d %d %d",name[i],&a[i],&b[i],&c[i]);
        sum[i]=a[i]+b[i]+c[i];
    }
    for(int j=0;j<N;j++){
        if(sum[j]>max){max=sum[j];std=j;}
    }
    printf("%s %d %d %d",name[std],a[std],b[std],c[std]);
    return 0;
}

by SunXiaolang @ 2024-10-18 06:17:07

@NoWalnut ```cpp

include<bits/stdc++.h>

using namespace std; int main() { int yu,shu,yin,big=-1,n,b1,b2,b3; string name,i; cin>>n; for (int l=1;l<=n;l++){ cin>>name>>yu>>shu>>yin; if (yu+shu+yin>big) { big=yu+shu+yin; b1=yu; b2=shu; b3=yin; i=name; } } cout<<i<<" "<<b1<<" "<<b2<<" "<<b3; }

by SunXiaolang @ 2024-10-18 06:17:25

#include<bits/stdc++.h>

using namespace std;
int main() {
    int yu,shu,yin,big=-1,n,b1,b2,b3;
    string name,i;
    cin>>n;
    for (int l=1;l<=n;l++){
        cin>>name>>yu>>shu>>yin;
        if (yu+shu+yin>big) {
            big=yu+shu+yin;
            b1=yu;
            b2=shu;
            b3=yin;
            i=name;
        }
    }
    cout<<i<<" "<<b1<<" "<<b2<<" "<<b3; 
}

by SunXiaolang @ 2024-10-18 06:18:21

你其实可以把判断放在第一个循环里

by SunXiaolang @ 2024-10-18 06:19:48

然后输入能用string，不用数组，接着后面三个数字用int来输入就行了

by NoWalnut @ 2024-10-18 09:08:26

@SunXiaolang ok，我明白了，非常感谢

by SunXiaolang @ 2024-10-18 20:16:37

@NoWalnut 求关

by NoWalnut @ 2024-10-29 21:16:35

@SunXiaolang 好