这题故意Unaccepted算不算违规?

P1001 A+B Problem

Panyang11 @ 2024-10-24 18:27:23

记录1
记录2
记录3



by Tobyzeng1306 @ 2024-10-25 17:49:48

@scratch_szc 因为你没过60,所以看不到


by scratch_szc @ 2024-10-25 17:50:37

@Tobyzeng1306 6


by Tobyzeng1306 @ 2024-10-25 17:52:04

你确定他是故意的,是你没输出对


by scratch_szc @ 2024-10-25 17:52:56

@Tobyzeng1306 @Grammar__hbw 确实,我mle了,求改


#include<bits/stdc++.h>
using namespace std;
const int N=11;
int mp1[N][N];
int mp[N][N];
int fx[4]={1,0,-1,0};
int fy[4]={0,1,0,-1};
void tu(int x,int y){
    //-1=可以走,-2不可以走
    for(int i=1;i<=N;i++){
        for(int j=1;j<=N;j++){
            mp[i][j]==-1;
            mp1[i][j]==-1;
        }
        mp[rand()%N+1][rand()%N+1]=-2;//随机数随机
        mp1[rand()%N+1][rand()%N+1]=-2;
        mp[N][N]=x;
        mp1[N][N]=y;
    }
}
int dfs1(int x,int y){//搜mp
    for(int i=0;i<4;i++){
        int dx=x+fx[i],dy=y+fy[i];
        if(dx<N&&dx>0&&dy<N&&dy>0&&mp[dx][dy]!=-2)dfs1(dx,dy);
        if(dx==N&&dy==N)return mp[N][N];
    }
}
int dfs2(int x,int y){//搜mp1
    for(int i=0;i<4;i++){
        int dx=x+fx[i],dy=y+fy[i];
        if(dx<N&&dx>0&&dy<N&&dy>0&&mp1[dx][dy]!=-2)dfs2(dx,dy);
        if(dx==N&&dy==N)return mp1[N][N];
    }
}
int main(){
    srand(time(NULL));
    int a,b;
    scanf("%d%d",&a,&b);
    tu(a,b);
    int t=dfs1(1,1);
    int v=dfs2(1,1);
    cout<<t+v;
}

by Lucas2024 @ 2025-01-02 20:04:07

@$[$scratch$_$szc$](luogu://user/1260767)$你没A$,$A了才能看

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