LacusMortis @ 2024-10-26 00:09:17
#include<iostream>
using namespace std;
int main()
{
int n,m,a[1000][1000],x1,x2,y1,y2;
cin>>n>>m;
for(int i=0;i<m;i++)
{cin>>x1>>x2>>y1>>y2;
for(int j=x1;j<=x2;j++)
for(int k=y1;k<=y2;k++)
a[j][k]++;}
for(int i=0;i<n;i++)
{for(int j=0;j<n;j++)
cout<<a[i][j]<<' ';
cout<<endl;}
return 0;
}
by postpone @ 2024-10-26 01:30:23
@LacusMortis 复杂度
by postpone @ 2024-10-26 01:34:41
vector f(n + 2, vector<int>(n + 2));
for (int i = 0; i < m; i++) {
int x, y, u, v;
cin >> x >> y >> u >> v;
f[x][y]++;
f[x][v + 1]--;
f[u + 1][y]--;
f[u + 1][v + 1]++;
}
vector pre(n + 1, vector<int>(n + 1));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
pre[i][j] = pre[i - 1][j] + pre[i][j - 1] - pre[i - 1][j - 1] + f[i][j];
}
}
by niuniudundun @ 2024-11-06 20:27:30
@LacusMortis
by niuniudundun @ 2024-11-06 20:36:17
@LacusMortis 求关
by Jiangminghui123 @ 2024-11-07 13:44:53
@LacusMortis a数组开1001大小