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P5735 【深基7.例1】距离函数

zhuzhu0307 @ 2024-10-26 13:07:42

略。


by rabbit_Cicy @ 2024-10-26 13:10:14

#include<bits/stdc++.h>
using namespace std;

double dis(double x1,double y1,double x2,double y2){
    double s=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
    return s;
}

int main(){
    double x1, x2, x3, y1, y2, y3;
    cin>>x1>>y1>>x2>>y2>>x3>>y3;
    double ans=dis(x1,y1,x2,y2)+dis(x2,y2,x3,y3)+dis(x3,y3,x1,y1);
    printf("%.2lf",ans);
    return 0;
}

求关。。。


by zhuzhu0307 @ 2024-10-26 13:56:25

已关。。。


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