lininglong2012 @ 2024-10-27 09:09:03
#include<bits/stdc++.h>
using namespace std;
int main(){
string n;
cin>>n;
char a[n.size()]={0};
for (int i = 0; i < n.size(); i++)
{
a[n.size()-i]=n[i];
}
for (int i = 0; i < n.size()+1; i++)
{
cout<<a[i];
}
return 0;
}
by _A8cde_ @ 2024-10-27 09:15:25
第二个循环的i初始化成1就可以了
#include<bits/stdc++.h>
using namespace std;
int main(){
string n;
cin>>n;
char a[n.size()]={0};
for (int i = 0; i < n.size(); i++)
{
a[n.size()-i]=n[i];
}
for (int i = 1; i < n.size()+1; i++)
{
cout<<a[i];
}
return 0;
}
by _A8cde_ @ 2024-10-27 09:20:18
互关么
by _A8cde_ @ 2024-10-27 09:30:21
@lininglong2012