五十分WA代码求调

#include<bits/stdc++.h>
using namespace std;
int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);cout.tie(0);
    int t,n,m,k,x,y,d;
    cin>>t;
    for(int i=1;i<=t;i++){
        cin>>n>>m>>k>>x>>y>>d;
        char s[n+5][m+5];
        int ss[n+5][m+5]={};
        for(int i=1;i<=n;i++){
            for(int j=1;j<=m;j++){
                cin>>s[i][j];
            }
        }
        int ans=1;
        ss[x][y]=1;
        while(k--){
            if(d==0){
                if(s[x][y+1]=='.'){
                    if(ss[x][y+1]==0){
                        ans++;
                        ss[x][y+1]=1;
                    }
                    y++;
                    printf("(%d,%d) %d %d\n",x,y,k,ans);
                    continue;
                }
                else{
                    printf("东-->南 %d %d\n",k,ans);
                    d++;

                    continue;
                }
            }
            if(d==1){
                if(s[x+1][y]=='.'){
                    if(ss[x+1][y]==0){
                        ans++;
                        ss[x+1][y]=1;
                    }
                    x++;
                    printf("(%d,%d) %d %d\n",x,y,k,ans);
                    continue;
                }
                else{
                    printf("南-->西 %d %d\n",k,ans);
                    d++;

                    continue;
                }
            }
            if(d==2){
                if(s[x][y-1]=='.'){
                    if(ss[x][y-1]==0){
                        ans++;
                        ss[x][y-1]=1;
                    }
                    y--;
                    printf("(%d,%d) %d %d\n",x,y,k,ans);
                    continue;
                }
                else{
                    printf("西-->北 %d %d\n",k,ans);
                    d++;

                    continue;
                }
            }
            if(d==3){
                if(s[x-1][y]=='.'){
                    if(ss[x-1][y]==0){
                        ans++;
                        ss[x-1][y]=1;
                    }
                    x--;
                    printf("(%d,%d) %d %d\n",x,y,k,ans);
                    continue;
                }
                else{
                    printf("北-->东 %d %d\n",k,ans);
                    d=0;
                    continue;
                }
            }

        }
        cout<<ans<<endl;
    }
    return 0;
}