python只对4和5，求大佬解答

wzxcc @ 2024-11-08 18:52:22

p=int(input())
l=input()
z=[]
for j in range(p):
    z.append(input().split())
for k in z:
    if k[0]=="1":
        l+=k[1]
        print(l)
    elif k[0]=="2":
        l=l[int(k[1]):int(k[1])+int(k[2])]
        print(l)
    elif k[0]=="3":
        l=l[:int(k[1])]+k[2]+l[int(k[1]):]
        print(l)
    else:
        if k[1] in l:
            for w in range(len(l)-len(k[1])+1):
                if k[1]==l[w:w+len(k[1])]:
                    print(w)
                    break
        else:
            print(-1)

by 5k_sync_closer @ 2024-11-08 19:24:53

@wzxcc 行末有 \r，用 rstrip 去掉就行了

p=int(input())
l=input().rstrip('\r')
for i in range(p):
    s = input().rstrip('\r')
    k = s.split()
    if k[0]=="1":
        l+=k[1]
        print(l)
    elif k[0]=="2":
        l=l[int(k[1]):int(k[1])+int(k[2])]
        print(l)
    elif k[0]=="3":
        l=l[:int(k[1])]+k[2]+l[int(k[1]):]
        print(l)
    else:
        if k[1] in l:
            for w in range(len(l)-len(k[1])+1):
                if k[1]==l[w:w+len(k[1])]:
                    print(w)
                    break
        else:
            print(-1)

by 5k_sync_closer @ 2024-11-08 19:25:17

好像用的是 c++ 代码块，不管了

by wzxcc @ 2024-11-08 19:38:17

@5k_sync_closer 大哥为什么会多空格

by wzxcc @ 2024-11-08 19:43:29

@5k_sync_closer 谢谢大哥我懂了，题目好阴险，能问一下这种空格题目常见吗，我小白

by Stone165 @ 2024-11-26 08:47:56

@5k_sync_closer我也是同样的问题，感谢大佬